0=635-16x^2

Solution for 0=635-16x^2 equation:

0=635-16x^2

We move all terms to the left:

0-(635-16x^2)=0

We add all the numbers together, and all the variables

-(635-16x^2)=0

We get rid of parentheses

16x^2-635=0

a = 16; b = 0; c = -635;
Δ = b2-4ac
Δ = 02-4·16·(-635)
Δ = 40640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{40640}=\sqrt{64*635}=\sqrt{64}*\sqrt{635}=8\sqrt{635}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{635}}{2*16}=\frac{0-8\sqrt{635}}{32}
=-\frac{8\sqrt{635}}{32}
=-\frac{\sqrt{635}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{635}}{2*16}=\frac{0+8\sqrt{635}}{32}
=\frac{8\sqrt{635}}{32}
=\frac{\sqrt{635}}{4}
$